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Diffstat (limited to 'spec/ruby/core/enumerable/minmax_by_spec.rb')
-rw-r--r-- | spec/ruby/core/enumerable/minmax_by_spec.rb | 44 |
1 files changed, 44 insertions, 0 deletions
diff --git a/spec/ruby/core/enumerable/minmax_by_spec.rb b/spec/ruby/core/enumerable/minmax_by_spec.rb new file mode 100644 index 0000000000..c92eb381a4 --- /dev/null +++ b/spec/ruby/core/enumerable/minmax_by_spec.rb @@ -0,0 +1,44 @@ +require File.expand_path('../../../spec_helper', __FILE__) +require File.expand_path('../fixtures/classes', __FILE__) +require File.expand_path('../shared/enumerable_enumeratorized', __FILE__) + +describe "Enumerable#minmax_by" do + it "returns an enumerator if no block" do + EnumerableSpecs::Numerous.new(42).minmax_by.should be_an_instance_of(Enumerator) + end + + it "returns nil if #each yields no objects" do + EnumerableSpecs::Empty.new.minmax_by {|o| o.nonesuch }.should == [nil, nil] + end + + it "returns the object for whom the value returned by block is the largest" do + EnumerableSpecs::Numerous.new(*%w[1 2 3]).minmax_by {|obj| obj.to_i }.should == ['1', '3'] + EnumerableSpecs::Numerous.new(*%w[three five]).minmax_by {|obj| obj.length }.should == ['five', 'three'] + end + + it "returns the object that appears first in #each in case of a tie" do + a, b, c, d = '1', '1', '2', '2' + mm = EnumerableSpecs::Numerous.new(a, b, c, d).minmax_by {|obj| obj.to_i } + mm[0].should equal(a) + mm[1].should equal(c) + end + + it "uses min/max.<=>(current) to determine order" do + a, b, c = (1..3).map{|n| EnumerableSpecs::ReverseComparable.new(n)} + + # Just using self here to avoid additional complexity + EnumerableSpecs::Numerous.new(a, b, c).minmax_by {|obj| obj }.should == [c, a] + end + + it "is able to return the maximum for enums that contain nils" do + enum = EnumerableSpecs::Numerous.new(nil, nil, true) + enum.minmax_by {|o| o.nil? ? 0 : 1 }.should == [nil, true] + end + + it "gathers whole arrays as elements when each yields multiple" do + multi = EnumerableSpecs::YieldsMulti.new + multi.minmax_by {|e| e.size}.should == [[1, 2], [6, 7, 8, 9]] + end + + it_behaves_like :enumerable_enumeratorized_with_origin_size, :minmax_by +end |