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#!/usr/local/bin/ruby
#
# pi.rb
#
require "bigdecimal"
#
# Calculates 3.1415.... (the number of times that a circle's diameter
# will fit around the circle) using J. Machin's formula.
#
def big_pi(sig) # sig: Number of significant figures
exp = -sig
pi = BigDecimal::new("0")
two = BigDecimal::new("2")
m25 = BigDecimal::new("-0.04")
m57121 = BigDecimal::new("-57121")
u = BigDecimal::new("1")
k = BigDecimal::new("1")
w = BigDecimal::new("1")
t = BigDecimal::new("-80")
while (u.exponent >= exp)
t = t*m25
u,r = t.div(k,sig)
pi = pi + u
k = k+two
end
u = BigDecimal::new("1")
k = BigDecimal::new("1")
w = BigDecimal::new("1")
t = BigDecimal::new("956")
while (u.exponent >= exp )
t,r = t.div(m57121,sig)
u,r = t.div(k,sig)
pi = pi + u
k = k+two
end
pi
end
if $0 == __FILE__
if ARGV.size == 1
print "PI("+ARGV[0]+"):\n"
p big_pi(ARGV[0].to_i)
else
print "TRY: ruby pi.rb 1000 \n"
end
end
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